A lot of 20 bulbs contain 4 defective ones. One bulb is drawn at random from the lot.
What is the probability that this bulb is defective? Suppose the bulb drawn in previous
case is not defective and is not replaced. Now one bulb is drawn at random from the rest.
What is the probability that this bulb is not defective?
Answers
Answered by
18
Answer:
1/4
15/19
Step-by-step explanation:
Total no. of bulbs=20
No. of defective bulbs=4
No. of good bulbs=16
P(Of defective bulb)-4/20= 1/5
P(not defective....after 1 not defective ws removed n not replaced)= 15/19
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