A lot of 20 bulbs contain 6 defective ones. One bulb is drawn at random from the lot. What is
the probability that this bulb is good?
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Step-by-step explanation:
Total no. of bulbs =20
No. of defective bulbs =4
Therefore,
P(getting a defective bulb)=
total no. of bulbs
No. of defective bulbs
=
20
4
=
5
1
Now,
One non defective bulb is drawn then the total numbers of bulb left is 19
Total numbers of bulbs =19
No. of defective bulbs =4=4
No. of non-defective bulbs =19−4=15
P(bulb is not defective)=
total numbers of bulbs
No. of non-defective bulbs
=
19
15
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