Math, asked by Anonymous, 11 months ago

A lot of 48mobile of which 42 are good,6 have only minor of defective varnika will buy a phone if it is good but the trader will only buy a mobile if it is has no major defect . one phone select at random from the lot. what is the probability that is (I) acceptable to varnika (ii) acceptable to trader​

Answers

Answered by jagdishgarg2004
3

Answer:

P(it is acceptable to Varnika)=42/48=7/8

P(it is acceptable to trader)=48/48=1

Step-by-step explanation:

Total number of mobile phones=48

No.of good mobile phones = 42

P (it is acceptable to Varnika) = 42/48 = 7/8

No.of mobiles without major defects=48

P (it is acceptable to trader) = 48/48 = 1

Answered by anshuace
2

Answer:

(l)7/8

(ll) 1

Step-by-step explanation:

n(s)=48

good mobiles=42

mobiles with minor defect= 6

varnika= good mobiles= 42

trader = good mobiles+ mobile with minor defect =48

(l) P(acceptable to varnika) =42/48 =7/8

(ll) P(acceptable to trader) =48/48= 1

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