Math, asked by michellevalliazham, 5 months ago

A lottery-ticket cost 4 dollars. Three boys: Paul, Peter, and Robert made a contribution and bought two tickets. Paul gave 1 dollar, Peter gave 3 dollars, and Robert gave 4 dollars.
One of the tickets they bought won them 1000 dollars.
The boys shared the award fairly, meaning in proportion to their contributions.
How much did Peter receive?

gaurinambiar: The answer is dollar 375

neolaaugustine3: 1000 divided by 8 = 125 x 3 { peter received 375 ]

gaurinambiar: This is because we have to use algebra ( 1x+3x+4x= 8x) and then using transposition x=1000÷8= 125 multiplied by 3 boys = 375

michellevalliazham: thanks

neolaaugustine3: : )

Answers

Answered by srisivasaji

Answer:

Step-by-step explanation:

The answer is dollar 375

1000 divided by 8 = 125 x 3 { peter received 375 ]

This is because we have to use algebra ( 1x+3x+4x= 8x) and then using transposition x=1000÷8= 125 multiplied by 3 boys = 375

Answered by neolaaugustine3

Answer:

{ peter received 375 ]

Step-by-step explanation:

1000 divided by 8 = 125 x 3

1000 ÷ 8 = 125

why were doing 1000 ÷ 8 because they won 1000 dollars

and bougth 2 tickets

1 ticket = 4

2 tickets = 4 + 4 = 8

so 1000 ÷ 8 = 125

now we do 125 x 3 because peter paid 3 dollars for the ticket

so 125 x 3 =375

peter got 375 out of 1000 dollars

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