A lotus flower is blooming in a lake . The flower is 1/2 metres above the surface of the lake. When the western wind blows, the flower droops at a distance of 2 metres from the base. Find the depth of the lake.
Answers
Answer:
3.7 m
Step-by-step explanation:
Given A lotus flower is blooming in a lake . The flower is 1/2 metres above the surface of the lake. When the western wind blows, the flower droops at a distance of 2 metres from the base. Find the depth of the lake.
The lotus flower is 1/2 m above the surface of the lake. Let us assume water has a depth y, then length of the stem will be (y + 1/2). The length of the stem is same. Now the distance of stem from original position(base) is 2 m
Taking water to be horizontal and stem to be straight(right angle(imagination),
using pythagoras theorem we have,
(y + 1/2)^2 = y^2 + 2^2
y^2 + 1/4 + 2. y. 1/2 = y^2 + 4
y^2 + 4 = y^2 + 1/4 + y
y = 4 - 1/4
y = 15 / 4
y = 3.7 m
Depth of lake is 3.7 m
Answer:
Step-by-step explanation:
Given A lotus flower is blooming in a lake . The flower is 1/2 metres above the surface of the lake. When the western wind blows, the flower droops at a distance of 2 metres from the base. Find the depth of the lake.
The lotus flower is 1/2 m above the surface of the lake. Let us assume water has a depth y, then length of the stem will be (y + 1/2). The length of the stem is same. Now the distance of stem from original position(base) is 2 m
Taking water to be horizontal and stem to be straight(right angle(imagination),
using pythagoras theorem we have,
(y + 1/2)^2 = y^2 + 2^2
y^2 + 1/4 + 2. y. 1/2 = y^2 + 4
y^2 + 4 = y^2 + 1/4 + y
y = 4 - 1/4
y = 15 / 4
y = 3.7 m
Depth of lake is 3