A lotus is seen 5 cm above the water level of a lake. With the onset of the wind it sinks in the water 10 cm away from its place. How deep is the water in that place?
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Assume the length of the lotus is in water x cm.
The length of the lotus above water is 5 cm. (given)
When it sinks, you'll see a right angled triangle will be formed with its dimensions as x cm, (x+5) cm, 10 cm.
Using pythagoras we get
(x+5)^2 = x^2 + 10^2
or 25 + 10 x = 100
or x = 7.5 cm,
Step-by-step explanation:
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