A lower and a pole stand vertically on the same level ground. It is observed
that the angles of depression of top and foot of the pole from the top of the
- lower of height 60 m is 30% and 60% respectively. Find the height of the pole
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REF.Image.
Let AB be the tower & CD be the
pole
As, given in the question BE = 20 m
∴ In △BCE,tan30
∘
=
CE
20
⇒
3
1
=
CE
20
∴CE=20
3
Now, in △ACEtan60
∘
=
CE
h
3
=
20
3
h
⇒h=60
∴ Height of tower = 60+20 = 80 m
solution
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