Question

A lump of ice falls from an aeroplane as it comes in to land .If the ice hits the ground with a vertical speed of 70m/s ,what was the height of the plane when the ice feii off . Take g = 10m/s^2

Answer 1

Answer:

245 metres

Explanation:

Given :

• Final velocity with which it hits the land = V = 70 m/s
• Acceleration of the lump of ice = a = 10 m/s²
• Initial velocity of the lump of ice = u = 0 m/s

To find :

• Height of the plane when the ice fell off = s

Using third equation of motion :

V²-u²=2as

70²-0²=2×10×s

4900-0=20s

4900=20s

S = 4900/20

S = 245 metres

The height of the plane when the lump of ice fell down is equal to 245 metres

Answer 2

✯✯ QUESTION ✯✯

A lump of ice falls from an aeroplane as it comes in to land .If the ice hits the ground with a vertical speed of 70m/s ,what was the height of the plane when the ice fell off . Take g = 10m/s^2..

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✰✰ ANSWER ✰✰

$\longmapsto\tt{Initial\:Velocity(u)=0}$

$\longmapsto\tt{Final\:Velocity(v)=70m/s}$

$\longmapsto\tt{Acceration(a)=10m/s}$

➥Now ,

➮Using 3rd Equation of Motion : -

$\longmapsto\tt{{v}^{2}-{u}^{2}=2as}$

➥Putting Values : -

$\longmapsto\tt{{(70)}^{2}-{(0)}^{2}=2(10)s}$

$\longmapsto\tt{4900-0=20s}$

$\longmapsto\tt{4900=20s}$

$\longmapsto\tt{s=\cancel\dfrac{4900}{20}}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{s}\orange{=}\purple{245m}}}$

☛So, The height of plane when ice fell off is 245m...