A lump of ice falls from an aeroplane as it comes in to land. If the ice hits the ground
with a vertical speed of 70m/s, what was the height of the plane when the ice fell off.
Take g=10m/s2
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Answer:
245m
Explanation:We have to use the formula of motion
V^2-u^2=2as
Putting
V=70m/s
U=0m/s(rest)
A=10m/s^2(acceleration due to gravity)
S=?
70^2-0^2=2(10)S
4900=20S
S=4900/20=245 m
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The height of the aeroplane when the ice fell from the aeroplane is equal to245meter
Explanation:
Given,
The acceleration due to gravity,g is 10 metre per second square.
The vertical speed of the ice when it falls on the ground,v is 70 metre per second
According to the formula of kinematics,
v²= 2gS ( the initial velocity of the ice is at rest and hence zero metre per second)
S= v²/2S
= 70•70/2• 10 =245meter
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