Question

A lump of iron of mass 2kg is heated from 40°C to 1000°⁰ , if the heat supplied is 192k.calc, find. 1. Thermal capacity 2. Specific heat of iron.​

Answer 1

Answer:

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Explanation:

$Given = \\ mass \: of \: iron \: (m) = 2.kg = 2000 \: g \\ Δt = (1000 - 40)°C = 960°C \\ heat \: energy \: supplied \: (Q) = 192 \: kcal = 192000 \: cal \\ \\ To \: find = \\ 1.Thermal \: Capacity \\ 2.Specific \: Heat \: capacity \: of \: iron \: (c)\\ \\ Solution = \\ so \: we \: know \: that \\ Q = m.c. \: Δt \\ 192000 = 960 \times 2000 \times c \\ 192000 = 1920000 \times c \\ c = \frac{192000}{1920000} \\ \\ c = 0.1 \: cal/g°C$

$now \: we \: know \: that \\ Thermal \: capacity = mass \: of \: object \times specific \: heat \: capacity \: \: of \: that \: object \\ = m \times c \\ = 2000 \times 0.1 \\ = 200 \: cal/°C$