A lump of iron of mass 8kg is hung in a brine of density 1100kg/m.If the iron volume of 0.001 m. find (a) the density of iron (b) the loss of weight in brine (c) the
apparent weight in brine.
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Explanation:
Mass of Iron = 8 kg
Volume of iron = 0.001 m^3
Density of Iron = Mass / Volume
= 8 / 0.001 = 8000 kg / m^3
Loss in weight = Buoyant Force
= Density of Brine × gravity × Volume immersed
= 1100 × 10 × 0.001 = 11 Newton
Apparent weight = Actual weight - Buoyant force
= ( Mass × gravity ) - 11
= ( 8 × 10 ) - 11
= 80 - 11 = 69 N .
Therefore, it is your answer.
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