Question

A lump of iron of mass 8kg is hung in a brine of density 1100kg/m​.If the iron volume of 0.001 m​. find (a) the density of iron (b) the loss of weight in brine (c) the
apparent weight in brine.

Answer 1

Explanation:

Mass of Iron = 8 kg

Volume of iron = 0.001 m^3

Density of Iron = Mass / Volume

= 8 / 0.001 = 8000 kg / m^3

Loss in weight = Buoyant Force

= Density of Brine × gravity × Volume immersed

= 1100 × 10 × 0.001 = 11 Newton

Apparent weight = Actual weight - Buoyant force

= ( Mass × gravity ) - 11

= ( 8 × 10 ) - 11

= 80 - 11 = 69 N .

Therefore, it is your answer.

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