Question

A lump of metal was transferred to 1 kg of water and the temperature of the water increased from 20ºC to 54ºC. Find:
(i) the energy lost be the metal
(ii) the energy gained by the water.

Answer 1

Answer:

34 is the correct answer of options no. 2

Answer 2

The energy lost be the metal  = The energy gained by the water = 142.324 kJ.

Given:

A lump of metal was transferred to 1 kg of water and the temperature of the water increased from 20ºC to 54ºC.

To find:

(i) The energy lost be the metal

(ii) The energy gained by the water.

Formula used:

ΔQ = m$C_{p$ ΔT

Where,    ΔQ = Change in energy

               m = mass

               $C_{p$ = Sp. heat

               ΔT = Change in temperature

Explanation:

• For the water the value of $C_{p$ = Sp. heat = 4.186 KJ./Kg. k.
• The energy lost be the metal  = The energy gained by the water
• Because no other system attached to it.
• Mass of water = 1 kg ..................given
• ΔT = Change in temperature = 54-20 = 34°c
• Note: temperature difference in °c and kelvin are same. don't confuse it.
• So The energy gained by the water =  m$C_{p$ ΔT

                                                                    = 1 × 4.186 ×34*

                                                                    =  142.324 kJ.

• The energy lost be the metal  = The energy gained by the water = 142.324 kJ.

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