Question

A lunar month consists of 27.3 days. If the distance between centres of earth and moon becomes double of its present value, then number of days in a lunar month will be

Answer 1

Answer:

54.6 days ( apprx.)

Actually the time will be more than the 54.6 days as the speed of moon will reduce due to reduced gravitational force

Step-by-step explanation:

Lunar Revolution period will drastically increase (more than 27.3 days).

Now, the perimeter of the the elliptical orbit increases by 4 times (≅ major axis increases by 4 times)

The current orbital length of moon

= Speed of moon x time taken for orbiting

= 1.022 km/s x  27.321661 days

= 1.022 x (27.321661  x 24 x 60 x 60) s = 2.41 x 10⁶ km

Assuming the speed of mean remains the same,

The orbital length after doubling the distance from earth = 4.83 x 10⁶ km

→  Speed of moon . x  =  4.83 x 10⁶

∴ x = lunar revolution time =  4.83 x 10⁶ / 1.022 =  4726027.39 seconds

x = 4726027.39726/(24*3600)  days =  54.6 days

Answer 2

Disclamer:

(Sorry this answer may be a little racist)

Step-by-step explanation:

Lunar month consists of 27.3 days

We know that dist b/w earth and moon = $\frac{1}{8.36*10x^{27} }$ of the radius of yo mama

Hence by the formula-

dist b/w earth to moon = ( $\int\limits^9_7 {x} \, dx$$\lim_{joe \to \infty} a_6$) x (radius of yo mama) = no of lunar days

Since the radius of yo mama is infinity,

no of lunar days = infinity

HOPE IT HELLEPD!!!

PLS MARK AS BARINLEDSS thansk