Question

A lustrous divalent metal ‘M’,used in galvanization when treated with sodium
hydroxide and hydrochloric acid separately in two different test tubes produced bubbles
in the reaction mixture:-
a) Identify the gas produced and write any two properties of it?
b)Write chemical equations for both the reactions happening in above two test tubes?​

Answer 1

Answer:

It is a lustrous, divalent element so it is a metal and only very reactive metal can react with NaOH. In the first case; a base reacts with a metal, and in the second case; an acid reacts with a metal. Hence, hydrogen gas is most likely to be produced during these reactions.

The evolution of hydrogen gas can be checked by bringing a burning matchstick or splinter near the evolved gas. The fact that the matchstick burns with a pop sound, shows that hydrogen gas is evolved.

The reactions can be shown by following equations:

2NaOH+Zn→Na2ZnO2+H2

2HCl+Zn→ZnCl2+H2

B) The element is a metal.

M+2NaOH->Na2MO2+H2

M+2HCl->MCl2+H2

hope it is helpful✌.

Answer 2

Answer:

pl mark the above as Brainliest