(a^m)^n=a^mn m(n-2)n(m-2)
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Answered by
6
a^(m + n) = a^mn
So,
m + n = mn
Now;
m(n - 2) + n(m - 2)
mn - 2m + mn - 2n
2mn - 2m - 2n
2mn - 2(m + n)
2mn - 2(mn)
2mn - 2mn = 0
Answered by
1
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