Question

अ मिनिमाइज ऑफ अ पिजन ऑफ रेगुलर सॉफ्टवेयर​

Answer 1

Answer:

Given :-

$</p><p>The \: length \: of \: a \: rectangle \: is \: 3 \\ \: units \: less \: than \: twice \: its \: width.$

$</p><p>Perimeter \: is \: 54 \: units.$

To Find :-

$The \: dimension$

Solution :-

$\dashrightarrow{\boxed{\red{\sf{Perimeter = 2(l + b)}}}}⇢ </p><p>$

$Perimeter=2(l+b)</p><p>$

Values :-

$\begin{gathered}\longrightarrow\sf{54 = (2x - 3 + x)} \\ \\ \longrightarrow\sf{54 = 2(3x - 3)} \\ \\ \longrightarrow\sf{3x - 3 = 27} \\ \\ \longrightarrow\sf{3x = 30} \\ \\ \longrightarrow\sf{x = \: }{\textsf{\textbf{10}}} \\ \\ \sf{Then, \: 2x - 3 = 2(10) - 3 = \: }{\textsf{\textbf{17.}}}\end{gathered}$

$⟶54=(2x−3+x)$

$⟶54=2(3x−3)$

$⟶3x−3=27$

$⟶3x=30$

$⟶x=10 </p><p>$

$Then,2x−3=2(10)−3=17.$

$Hence,$

$</p><p>Breadth = 10.$

$Length = 17.$

Answer 2

Answer:

please translate it in English

Explanation:

then I will surely answer