Question

A machine gun fires 10 bullets per second with speed
10 m/s. If mass of each bullet is 300 g, then the force
required to keep the gun stationary is
40 N
10 N
20 N
30 N​

Answer 1

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force required to hold gun

f=nmv

=10×300x10^-3×10

=30 Newton

Answer 2

CORRECT QUESTION

A machine gun fires 10 bullets per second with speed

10 m/s. If mass of each bullet is 300 g, then the force

required to keep the gun stationary is

(a) 4 N

(b) 1 N

(c) 2 N

(d) 3 N

ANSWER

The Force required is 3N

GIVEN

A machine gun fires 10 bullets per second with speed 10 m/s. If mass of each bullet is 300 g. q

TO FIND

The force required to keep the gun stationary.

SOLUTION

We can simply solve the above problem as follows;

To keep the gun stationery a force equal to recoil force of the gun should be applied.

We know that,

Force = Rate of change of momentum.

F = mv/t

Now,

Mass of 1 bullet = 300 grams = 0.3 kg

Velocity of bullet = 10m/s

Momentum of 1 bullet = Mass × velocity = 0.3 × 10 = 3 kgm/s

Momentum of 10 bullets = 3 × 10 = 30 kgm/s

Now,

Force = 30/10 = 3N

Hence, The Force required is 3N

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