a machine gun fires a bullet of mass 40 g with a velocity 1200ms.the man holding it,can exert a maximum force of 144N on the gun.how many bullets can he fire per second at the most?
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Answered by
596
Mass of each bullet = 40 g = .040 kg
Velocity of each bullet = 1200 m/s
Let 'n' be the number of bullets fired per second. Then, change in momentum of the bullets coming out per second is,
= force on the man
=> n (0.040)(1200) = 144
=> n = 3
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Answered by
252
F = nmv/t
n = Ft / (mv)
= (144 N × 1 s) / (40 × 10^-3 kg × 1200 m/s)
= 3
Man can fire 3 bullets per second
n = Ft / (mv)
= (144 N × 1 s) / (40 × 10^-3 kg × 1200 m/s)
= 3
Man can fire 3 bullets per second
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