Question

A machine gun fires a bullet of mass 40 g with a velocity 1200 ms⁻¹. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most?(a) 2 (b) 4(c) 1 (d) 3

Answer 1

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Answer 2

Answer: D) 3

Explanation:

Mass of each bullet = 40 g = .040 kg (Given)

Velocity of each bullet = 1200 ms⁻¹ (Given)

Maximum force exerted on the gun = 144N (Given)

Let the number of bullets fired per second be = n

Thus, the change in momentum of the bullets coming out per second is = force on the man

F = nmv/t

n = Ft/(mv)

= (144 N × 1 s) / (40 × 10^-3 kg × 1200 m/s)

= n = 3

Therefore, the man can fire 3 bullets per second.