A machine gun fires a bullet of mass 40 g with a velocity of 1200m/s The man holding it can exert maximum force of 144 N on the gun. How many bullets can be fired per second at the most?
Answers
Answered by
2
Explanation:
Step 1: Newton’s Second Law,
From Newton's second law
F=
dt
dP
....(1)
Where, P=mv is the momentum
Step 2: Total bullets fired per sec
Let n be the total number of bullets fired
The force exerted by man must balance the change in momentum of the bullets per second.
∴P=nmv ; m and v are constant (Given)
⇒F=
dt
d
(nmv)
⇒
dt
dn
=
mv
F
=
40×10
−3
(kg)×1200(m/s)
144(N)
=3
Hence total number of bullets fired per second i.e.,
dt
dn
=3.
Hence, Option B is correct
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