a machine gun fires a bullet of mass 40g with a speed of 1200m/s . The person holding the gun can exert a maximum force of 144N on it . what is the no.of bullet that can be fired from a bullet per second
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Answered by
27
By using Newton’s second law of motion
F = nmv/t
n/t = F / (mv)
= 144 N / (40 × 10^-3 kg × 1200 m/s)
= 3 bullets per second
He can fire 3 bullets per second
F = nmv/t
n/t = F / (mv)
= 144 N / (40 × 10^-3 kg × 1200 m/s)
= 3 bullets per second
He can fire 3 bullets per second
Answered by
2
Answer:
Explanation:
By using Newton’s second law of motion
F = nmv/t
n/t = F / (mv)
= 144 N / (40 × 10^-3 kg × 1200 m/s)
= 3 bullets per second
He can fire 3 bullets per second
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