Question

a machine gun fires a bullet of mass 50 gm with a velocity of 800 m÷s.the man holding the machine gun can exert a maximum force of 200 n.what is the maximum number of bullet he can fire per second​

Answer 1

Answer:

5

Step-by-step explanation:

mass of each bullet = 50g = 0.050 kg.

velocity of each bullet = 800 m/sec.

Let 'N' be the number of bullets that can be fired per second.

The change in momentum of bullets coming out per second = force on the man

F = nmv/t  

N * 0.050 * 800 = 200

N = 200/0.05 *800 =  5.

Number of bullets that can be fired per second = 5.

Answer 2

i dont wanna answer u so get lost