Question

A machine gun fires a bullet of mass 65 gram with a velocity of 1300 metre per second the man holding it can exert a maximum force of 169 newton

Answer 1

Answer:

hope this helps u...!.

Answer 2

Correct Question: A machine gun fires a bullet of mass 65 g with a velocity of 1300 m/s. The man holding it can exert a maximum force of 169 N on the gun. The number of bullets he can fire per second will be?

Answer:

The number of bullets man can fire will be 2.

Explanation:

Given;-

        Mass of bullet, m = 65 g

     Velocity of bullet, v = 1300 m/s

         Force on man, F = 169 N

Let the number of bullets man can fire per second be 'n'.

Now, we know that;-

  Force on Man = - Force on bullet

                    F  = dP/ dt [where P = momentum] ... by formula.

                     F = mv - 0/ t  [since, initial momentum = 0]

                     F = ( mv/t ) × n [where, n = number of bullets]

                 169 = 65 × 1300 × n / 1000 × 1

               1690 = 65 × 13 × n

               1690 = 845 × n

                     n = 1690/845

                    n = 2

Hence, the man can fire 2 bullets per second.

Hope it helps! ;-))