Question

A machine gun fires bullet at the rate of 600 bullets per minute with a speed of 200 m/s calculate force required to keep gun in position

Answer 1

Answer:

PLEASE GIVE ME A BRANLIAST ANSWER AND FOLLOW ME

U = 0

v= 200m/s

t = 600/60s = 1/10

m = 25g = 0.025

acceleration = ?

so

a=v-u/t

= 200-0/ 1/10

= 2000m/s²

force= ma

= 0.025× 2000

= 50N

hope it helps

Answer 2

Explanation:

U = 0

U = 0v= 200m/s

U = 0v= 200m/st = 600/60s = 1/10

U = 0v= 200m/st = 600/60s = 1/10m = 25g = 0.025

U = 0v= 200m/st = 600/60s = 1/10m = 25g = 0.025acceleration = ?

U = 0v= 200m/st = 600/60s = 1/10m = 25g = 0.025acceleration = ?so 

U = 0v= 200m/st = 600/60s = 1/10m = 25g = 0.025acceleration = ?so a=v-u/t

U = 0v= 200m/st = 600/60s = 1/10m = 25g = 0.025acceleration = ?so a=v-u/t= 200-0/ 1/10

U = 0v= 200m/st = 600/60s = 1/10m = 25g = 0.025acceleration = ?so a=v-u/t= 200-0/ 1/10= 2000m/s²

U = 0v= 200m/st = 600/60s = 1/10m = 25g = 0.025acceleration = ?so a=v-u/t= 200-0/ 1/10= 2000m/s²force= ma

U = 0v= 200m/st = 600/60s = 1/10m = 25g = 0.025acceleration = ?so a=v-u/t= 200-0/ 1/10= 2000m/s²force= ma= 0.025× 2000

U = 0v= 200m/st = 600/60s = 1/10m = 25g = 0.025acceleration = ?so a=v-u/t= 200-0/ 1/10= 2000m/s²force= ma= 0.025× 2000= 50N

U = 0v= 200m/st = 600/60s = 1/10m = 25g = 0.025acceleration = ?so a=v-u/t= 200-0/ 1/10= 2000m/s²force= ma= 0.025× 2000= 50Nhope it helps