Question

A machine gun fires n bullets per second and the mass of each bullet is m. If v is the speed of each bullet, then the average force exerted on the machine gun is

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Answer 1

Answer:

Explanation:

Initial velocity of bullet   u=0

Final velocity of bullet  is v

Change in momentum of one bullet ΔP1  = mv−0=mv

In one second, number of bullets fired is n

So change in momentum of bullets in one second  =ΔP=nΔP1  = mnv

Force exerted on machine gun by bullets  F= ΔP/Δt

⟹ F= mnv/ 1  = mnv

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Answer 2

answer :- see the attachment