A machine gun has a mass 4kg. It fries bullet of mass 50g each at a rate 30
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Given the mass of the gun, M = 4 kg,
mass of the bullet, m = 0.05 kg
Speed of the bullet, v = 500 m/s.
Let the velocity of recoil of the gun = V
Using conservation of momentum, we get
Momentum after = momentum before
MV – mv = 0 (as initial momentum was zero)
or, MV = mv
or, 10*V = 500*0.05
or, V = 25/10 = 2.5 m/s
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