A machine gun having a power 27 kw fires 'n' bullets per second each of mass 10 gm. If the
velocity of each bullet is 300 ms -1, the value of 'n' is
60
120
600
300
Answers
Given :
- Power of machine Gun, P = 27 kW = 27 × 1000 w = 27,000 w
- n number of bullets are fired per second so time , t = 1 s
- Velocity of each bullet, v = 300 ms⁻¹
- Mass of each bullet, m = 10 gm = 10/1000 kg = 0.01 kg
To find :
Value of 'n' = ?
Knowledge required :
- Formula to calculate Kinetic energy
- Relation between Power and Kinetic Energy
[ Where K.E. is the kinetic energy of a body, mass is m , velocity is v , P is power and t is time ]
Solution :
Calculating K.E. of 'n' bullets
Calculating value of 'n'
Therefore,
- Number of bullets is equal to 60 .
Option (1) 60 is correct.
Answer:
a) 60
Explanation:
Given that, a machine gun having a power 27 kw fires 'n' bullets per second each of mass 10 gm. If the velocity of each bullet is 300 m/s.
We have to find the value of n.
Potential energy is 27 kW or 27000 W (1kW = 1000W), mass is 10 gm or 0.01 kg, time is 1 sec and velocity is 300 m/s.
Energy which a body possesses by virtue of being in motion is known as Kinetic energy.
Kinetic energy = 1/2 mv²
Substitute the values,
→ K.E. = 1/2 × 0.01 × (300)²
→ K.E. = 0.01/2 × 90000
→ K.E. = 450 J
Power = 27000 W
We know that, the relation between Kinetic energy, power and time is:
Power = Kinetic energy/Time
And as per given condition we have to find the 'n' number of bullets.
Power = n × Kinetic energy/Time
Substitute the values,
→ 27000 = n × 450 /1
→ 27000/450 = n
→ 60 = n
Hence, the value of n is 60.