A machine gun of mass 10kg fires 20g bullets at the rate of 10 bullets per second, with the speed of 500 m/s. What force is necessary to hold the gun in position?
Answers
Answered by
178
Final Answer : 100N
Steps :
1 ) We know that, Force is rate of change of momentum.
Here, momentum of bullet is changed from rest to 500m/s.
To control this change, we require force to hold the gun.
This, force.
2) Mass of bullet, m = 20/1000kg
No. of bullets fired per sec, = 10
Speed of bullet, = 500m/s
|F| = mass of bullet * speed of bullet * No. of bullets fired per sec.
= 20/1000* 500 * 10
= 100N
Therefore, 100 N of Force is required oposite to jer produced by recoil of gun.
Steps :
1 ) We know that, Force is rate of change of momentum.
Here, momentum of bullet is changed from rest to 500m/s.
To control this change, we require force to hold the gun.
This, force.
2) Mass of bullet, m = 20/1000kg
No. of bullets fired per sec, = 10
Speed of bullet, = 500m/s
|F| = mass of bullet * speed of bullet * No. of bullets fired per sec.
= 20/1000* 500 * 10
= 100N
Therefore, 100 N of Force is required oposite to jer produced by recoil of gun.
Answered by
34
the force required to hold will be 100 Newton
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