Question

a machine is driven by a 100 kg mass that falls 8 meter it lifts a load of 500kg vertically upward (g=10m/s2) calculate the work done by a falling mass​

Answer 1

Explanation:

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Answer 2

Answer:

Given:–

• Mass = 100kg

• Displacement = 8.0m

• Load = 500kg

• Time = 4.0s

• g = 10ms^-2

To find:–

• Force exerted

• Work done

• Power input

• Power output if efficiency is 60%

As we know:–

Step by step explaination:–

(a) As force exerted by falling mass = mass × g

So, mass is 100 kg and g is 10ms^-2.

That is,

→ 100 × 10

→ 1000 N

(b) As work done by the falling mass = force exerted × displacement .

That is,

→ mg × d

→ 1000 × 8

→ 8000J

(c) As power input = work done on machine/time.

That is,

→ 2000W

(d) Now we have to calculate the power output if efficiency is 60%.

As,

efficiency = power output/power input

Thus,

Power output = power input × efficiency

That is,

→ 2000 W = 0.6

→ 1200 W