a machine is purchased for 62500 its value depreciates at the rate of 8% per annum what will be its value 2 years
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Answered by
8
Value after two years = 62500× 92/100 × 92/100 = 52900 answer.
Answered by
7
Value after 2 years= P{1-(r/100)}^n
=62500 {1-(8/100)}^2
=62500*( 23/25)^2
= 52900
=62500 {1-(8/100)}^2
=62500*( 23/25)^2
= 52900
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