Question

a machine is purchased for 625000 its value depreciated at the rate of 8 per annum what will be its value after 2 years

Answer 1

Hey,.
Given:- Principal =Rs 625000
rate = 8% per annum
time= 2 yrs.
So, Amount = P(1-r/100)^T(since the value is depreciated)
=625000(1-8/100)^2
=625000(92/100*92/100)
= Rs 529000.

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Answer 2

The value of the machine after two years would be 5,29,000.

Step-by-step explanation:

Given that,

Cost Price of the machine = 6,25,000

Depreciation = 8% p.a.

Time = 2 years

To find,

The value of the machine after two years = ?

So, we will find it using the formula $P(1-r/100)^T$

The price of the machine after two years = $P(1-r/100)^T$

= $6,25,000(1 - 8/100)^2$

= 6,25,000$(92/100)^2$

= 6,25,000 × (92/100) × (92/100)

= 5,29,000

Thus, the machine's cost would be 5,29,000.

Learn more about 'Depreciation' here:

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