A machine is purchased for Rs.6,25,000. Its value depreciates at the rate of 10% p.a then its value after 2 years will be
Answers
Answer:
Rs.5,06,250
Step-by-step explanation:
Depreciation is like compound interest with the following basic differences:
1. Rate of interest per cent per year = Rate of depreciation per cent per year
2. In compound interest, the value of the initial amount increases whereas in depreciation, the value decreases (or depreciates).
Note: You can also think of depreciation as compound interest with a negative rate of interest.
Calculations:
P = initial value in Rupees = 625000
R = rate of depreciation per cent per year = 10
T = time period in years = 2
A = depreciated value at the end of time period T
A = P*(1 - R/100)^T [Note the "-" sign, in CI calculation, it is "+"]
= 625000*(1 - 10/100)^2
= 625000*(1 - 0.1)^2
= 625000*(0.9)^2
= 625000*(0.81)
= 506250
Answer: The value of the machine after two years is Rs.5,06,250. This value is called the depreciated value.