Question

a machine is purchased which will produce earning of Rs 20000 per year while lasts.the machine cost Rs 120000 and will have a salvag value of Rs 20000 when it is12 percent can be earned on alternative investments what should be the minimu life of the machine to make it a more attractive investment compared to alternative investments?​

Answer 1

Answer:

hi

Step-by-step explanation:

#include<stdio.h>

#include<conio.h>

int main()

{

int year=0, invest, alternate;

while(alternate>invest)

{

year++; //year = year + 1;

// yearly produce income form alternate solution

// 9 % of 1000 = 90

alternate = year * 90;

// yearly produced income from machine

// 1000 per year - [6000(machine cost) - 2000(salvage or scrap value of machine)]

// 1000 * year - [6000-2000]

invest = (1000*year) - 4000;

}

printf("The Life of Machine: %d years", year);

}

Output:

The Life of Machine: 5 years