A machine M can print ten thousand books in 6 hours machine N can print the same number of books in 8 hours while machine S can print them in 10 hours. All the machines started at 10 a.m. while machine M is closed at 12 noon and the remaining two machines complete the work. Approximately at what time will the work be finished
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Work done by M=1/6t
Work done by N=1/8t
Work done by S=1/10t
In this case time is :12.00-10.00=2hrs
The work done in 2hrs=2(1/6+1/8+1/0)
=(15+20+12)/120 × 2
=47/60
Work remaining=60/60-47/60
13/60
We form an equation to get t in doing the remaining work by N and S :
t(1/8+1/10)=13/60
9/40t=13/60
t=13/60 × 40/9=26/27
26/27 minutes
Convert this to seconds :26/27×60
=57seconds 7 milliseconds
Add this to 12.00 noon
12:00:57:07p.m
Work done by N=1/8t
Work done by S=1/10t
In this case time is :12.00-10.00=2hrs
The work done in 2hrs=2(1/6+1/8+1/0)
=(15+20+12)/120 × 2
=47/60
Work remaining=60/60-47/60
13/60
We form an equation to get t in doing the remaining work by N and S :
t(1/8+1/10)=13/60
9/40t=13/60
t=13/60 × 40/9=26/27
26/27 minutes
Convert this to seconds :26/27×60
=57seconds 7 milliseconds
Add this to 12.00 noon
12:00:57:07p.m
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