Math, asked by dominicasoft1097, 1 year ago

A machine M can print ten thousand books in 6 hours machine N can print the same number of books in 8 hours while machine S can print them in 10 hours. All the machines started at 10 a.m. while machine M is closed at 12 noon and the remaining two machines complete the work. Approximately at what time will the work be finished

Answers

Answered by santy2
12
Work done by M=1/6t

Work done by N=1/8t

Work done by S=1/10t

In this case time is :12.00-10.00=2hrs

The work done in 2hrs=2(1/6+1/8+1/0)

=(15+20+12)/120 × 2

=47/60

Work remaining=60/60-47/60

13/60
We form an equation to get t in doing the remaining work by N and S :

t(1/8+1/10)=13/60

9/40t=13/60

t=13/60 × 40/9=26/27

26/27 minutes

Convert this to seconds :26/27×60
=57seconds 7 milliseconds

Add this to 12.00 noon

12:00:57:07p.m
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