Question

. A machine of mechanical advantage 12 is used for a load of 120 kgf . Find the required effort.​

Answer 1

Answer:

ans is 10

hope it helps

Answer 2

Answer:

Given :-

• A machine of mechanical advantage 12 is used for a load of 120 kgf.

To Find :-

• What is the required effort.

Formula Used :-

$\clubsuit$ Mechanical Advantage Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{Mechanical\: Advantage =\: \dfrac{Load}{Effort}}}}\: \: \: \bigstar$

Solution :-

Given :

• Mechanical Advantage = 12
• Load = 120 kgf

According to the question by using the formula we get,

$\implies \sf\bold{\purple{Mechanical\: Advantage =\: \dfrac{Load}{Effort}}}$

$\implies \sf 12 =\: \dfrac{120}{Effort}$

By doing cross multiplication we get,

$\implies \sf 12 \times Effort =\: 120$

$\implies \sf Effort =\: \dfrac{120}{12}$

$\implies \sf Effort =\: \dfrac{10}{1}$

$\implies \sf\bold{\red{Effort =\: 10\: kgf}}$

$\therefore$ The effort required is 10 kgf .