A machine part is in the shap of a cone mounted on a hemisphere of radius 24cm .The total heaight of the machine part is 5cm. Find the total Surface area of the part and iron required to make the part?
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Answer:
Length = root (r² + h²)
= root (24² + 5²)
= root (576 + 25)
= root 601
= 24.51 approximately
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The lateral surface area of a cone is pi*r*l
= 22/7 * 24 * 24.51
= 22/7 * 588.24
= 12941.28/7
= 1848.75cm²
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The area of the circle in the bottom is pi*r²
= 22/7 * 24 * 24
= 22/7 * 576
= 12672/7
= 1810.28cm²
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Hence the total surface area will be :
Lateral surface area + Circle area
= 1848.75 + 1810.28 = 3659.03cm²
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Final Answer : 3659.03cm²
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