A machines 12% efficient if useful work done by the machines 6 joules then calculate the total energy consumed by the machime
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Answered by
7
Answer:
given efficiency of the machine is 75% and it is spending 12 J of energy to lift that mass
according to the law of conservation of energy the stored potential energy in the mass will be converted to its kinetic energy. hence,
(12×75)/100=(m×v
2
)/2
V=
18
m/s
i know its not same ques which u asked but its same type ques jst value change kr dena
Answered by
5
Answer:
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