Question

A magnet is parallel to a uniform
magnetic field. The work done in rotating
the magnet through 60°is 8 x 10-5J. The
work done in rotating through another
30° is
(A) 4x10-5J
(B) 6x10-5
(C) 8x10-5J
(d) 2X 10–5j​

Answer 1

Answer:

c

Explanation:

using relation delta U = - WORKDONE

in given case

MB cos(60+30) - MBcos(60) = - work done

calculate to get answer c

NOTE this relation is only applicable in conservative feild