A magnet makes 10 oscillations per minute at a place where the angle of dip is 45º and the
total intensity is 0.4 gauss. Calculate the number of oscillations made per sec by the same
magner at another place where the angle of dip is 60° and the intensity of the field is equal
to 0.5 gauss
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Answer: A magnet makes 5 oscillations per minute in H = 030.3 x 10‐4 T. By what amount the field should be increased so that the number of oscillations is 10 in the same time? 1) 0.3 x 10‐4 T2) 0.6 x 10‐4 T 3) 0.9 x 10‐4 T 4) 1.2 x 10‐4 T
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