Question

A magnet makes 5 oscillation per minutes in earths magnetic field (H=0.3 gauss); By what amount should the field be increased so that the magnet may make 10 oscillation per minute.​

Answer 1

Explanation:

T =2π √I/MH

thus,

f=1/2π *√MH/I

f1/f2 =√H1/H2

5/10 = √0.3/H2

1/2 = √0.3/H2

On squaring both sides,

1/4= 0.3/H2

thus, H2 = 0.3*4 or

H=1.2 Gauss

Answer 2

Concept:

Magnetic forces are observable in a magnetic field, which is a vector field in the vicinity of a magnet, electric current, or changing electric field. Moving electric charges and inherent magnetic moments of elementary particles associated with a fundamental quantum characteristic known as spin form a magnetic field. Both the magnetic and electric fields are components of the electromagnetic force, which is one of nature's four fundamental forces.

Find:

The amount of magnetic field should be increased to make ten oscillations.

Solution:

Time period,

$T= 2\pi \sqrt{\frac{I}{MB} } \\T \propto \frac{1}{\sqrt{B} }$

$\frac{T_1}{T_2}=\sqrt{\frac{B_2}{B_1} } \\\frac{10}{5}=\sqrt{\frac{B_2}{0.3} } \\\\B_2=1.2Gauss$

Hence, the magnetic field should be increased by $0.9Gauss$.

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