A magnet makes an angle of 45° with the horizontal in a plane making an angle of 30° with the magnetic meridian. Find the true value of the dip angle at the place.
Answers
Give the vertical part of earth's attractive field a chance to be V and its even segment at attractive meridian be H.
At the point when the plunge needle is suspended at an edge of 30∘ to the earth attractive meridian then it makes an edge 45∘ with the even.
The curl is in a vertical plane making an edge of 45° with the attractive meridian.
Explanation:
Let the vertical component of earth's magnetic field be V and its horizontal component at magnetic meridian be H.
Then the angle of dip θ
at magnetic meridian will be given by
tanθ
=
V/H
...
...
[1]
When the dip needle is suspended at an angle of
30∘
to the earth magnetic meridian then it makes an angle
45∘
with the horizontal.
In this situation vertical component of earth's field responsible for its orientation with the horizontal direction, remains same as
V
but the component in horizontal direction becomes
Hcos30∘
So
tan45∘
=
V/Hcos30∘
⇒
V/H
=
cos30∘
...
...
.
[2]
Comparing [1] and [2] we get
tanθ
=
cos30∘
=
√3/2
⇒
θ=tan−1(√3/2)≈
40.9∘