Physics, asked by yesh123, 9 months ago

A magnet of dipole moment M is aligned in equilibrium position in a magnetic field of intensity B. The work done to rotate it through an angle  with the magnetic field is ​

Answers

Answered by Narinder1577
0

Answer:

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Answered by vinaypuja1524
0

Answer:

The work done in rotating the bar magnet is given by:

W=MB(1−cosθ)

Explanation:

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