Question

a magnet of length 0.1m and pole strength 10^-4Am. is kept in a magnetic field of 30Wb/m^2 at an angle 30 degree. the couple acting on it us​

Answer 1

Given

Pole strength m=10

−4

Am and length = 0.1m

τ=

M

×

B

=MBsinθ=m×(2l)×Bsinθ=10

−4

×0.1×30sin30

o

=1.5×10

−4

Nm.

Answer 2

Explanation:

A magnet of length 0.1m and pole strength 10

−4

Am. is kept in a magnetic field of 30Wb/m

2

at an angle 30

o

. The couple acting on it is 10

−4

Nm