A magnet of length 2l is bent at mid at 60°. Find the new length of bar magnet.
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Answer:
Answer:2L
Answer:2L Explanation:
Answer:2L Explanation:AC = AO +OC
Answer:2L Explanation:AC = AO +OC = 2L sin (60/20) + 2L sin (60°/2) (By Dividing 60/2. comes 30)
Answer:2L Explanation:AC = AO +OC = 2L sin (60/20) + 2L sin (60°/2) (By Dividing 60/2. comes 30) = 2L sin 30° = 2L×1 /2 = 2L
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