Question

A magnet of mass 0.072 kg has a magnetic movement 6×10^-7 . The density of magnet is 7200 kg /m^3 . The intensity of magnetization is

Answer 1

Answer:

A magnet of mass 0.072 kg has a magnetic moment 6 10-7 Am2. The density of the magnet is 7200 kg/m3.

The intensity of magnetization is. 6 A/m. 60 A/m. 0.06 A/m. 1 A /m.

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Answer 2

The intensity of magnetization is 0.06 A/m.

Given: The mass of magnet is 0.072 kg.

           The magnetic moment 6×10^-7 Am²

           The density of magnet is 7200 kg /m^3

To Find: The intensity of magnetization

Solution:

• The Intensity of Magnetisation is defined as the change in the magnetic moment per unit volume.
• The formula of Intensity of Magnetisation (I) is given as:

                 I = M ⁄ V       [ where M = Magnetic moment, V =  Volume ]

We know that, density = mass / volume

                    ∴ volume = mass / density.                        ......(1)

  We have mass = 0.072 kg and density = 7200 kg /m^3,

So, putting these values in (1), we get;

                      volume ( V ) = 0.072 / 7200

                                    = 1 × 10^-5 m³

Magnetic moment ( M ) = 6×10^-7 Am²

So, we use the formula for calculating the intensity of magnetization (I)

                       I = M / V

                         =  ( 6×10^-7 ) / 10^-5  A/m

                         = 0.06 A/m

Hence, the intensity of magnetization is 0.06 A/m.

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