Physics, asked by clinton9992, 10 months ago

A magnet suspended at 30^@ with magnetic meridian makes an angle of 45^@ with the horizontal. What shall be the actual value of the angle of dip?

Answers

Answered by deepakbhai1814
1

Answer:Explanation:

Let the vertical component of earth's magnetic field be V and its horizontal component at magnetic meridian be H.

Then the angle of dip  θ  at magnetic meridian will be given by

tanФ=V/H

When the dip needle is suspended at an angle of  30

to the earth magnetic meridian then it makes an angle  45 with the horizontal.

In this situation vertical component of earth's field responsible for its orientation with the horizontal direction, remains same as  v

but the component in horizontal direction becomes  H cos 30

V/H COS 30=tan 45

V/H=cos 30

Comparing [1] and [2] we get

tan 45=cos 30=√3/2

tan^-1[√3/2]=40.9 degree

Answered by Anonymous
1

Answer:

Declination :

The angle between geographical meridian and magentic meridian

Dip :

The angle made between earth total magentic field and its horizontal component

Angle of dip is maximum at poles

Angle of dip is minimum at equator

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