Question

A magnetic circuit with a single air gap. The core dimensions are: Cross-sectional area =
1.8 x

${10}^{10}$
m, Mean core length 1 = 0.6 m, Gap length = 2.3 * 10m, N= 83 tums, I =
1.5 A. Calculate Flux in the magnetic circuit.​

Answer 1

Answer:

The flux in the magnetic circuit is 1.224 * 10⁻¹ Wb.

Step-by-step explanation:

Given data:

Area of cross-section, A = 1.8 * 10¹⁰ m²

Mean core length, Lc = 0.6 m

Gap length, g = 2.3 * 10 m

N = 83 turns

Current, I = 1.5 A

To find: Flux “∅” in the magnetic circuit

Let reluctance of the core be “Rc” and reluctance of the gap be “Rg”. Also, µo = 4π * 10^-7 H/m.

Since we are provided with any information about the permeability in the question. Let us assume that the permeability “µ” of the core is infinite and thereby neglecting any effects of fringing fields at the air gap and leakage flux.

If µ→∞ , Rc = 0

∴ Rg

= g / (µo * A)  

= 2.3 * 10 / [4π * 10^-7 *1.8 * 10^10 ]

= 2.3 / 2260.8  

= 0.00101734  

= 1.0173 * 10³ A/Wb

Now, the flux “∅” in the magnetic circuit is given by

∅ = [N * I] / [Rc + Rg]

Or, ∅ = [83 * 1.5] / [0 + 1.017 * 10³]

Or, ∅ = 122.38 * 10⁻³ ≈ 1.224 * 10⁻¹ Wb