Question

A magnetic dipole of dipole moment 10(i+j+k) is placed in a magnetic field 0.6i+0.4j+0.5k, force acting on the dipole is

Answer 1

Answer:

Ans: Force Between Poles is 3.2 x 10-4 N ... The magnetic dipole moment of a bar magnet is given by.

Answer 2

Answer:

F= i + j - 2 k

Explanation:

Given that

Dipole moment ,M= 10 i + 10 j + 10 k

Magnetic filed ,B= 0.6 i + 0.4 j + 0.5 k

The force acting on the dipole is the cross product of magnetic dipole and the magnetic filed.

Therefore the force given as

F= M x B

F= (10 i + 10 j + 10 k) x ( 0.6 i + 0.4 j + 0.5 k )

We know that

i x j = k  , j x i = - k

j x k = i  , k x  j = - i

k x i = j   , i x k = - j

i x i = j x j= k x k = 0

F=0 - 6 k + 6 j  + 4 k + 0 - 4 i - 5 j + 5 i +0

F= i + j - 2 k

Therefore the force will be F= i + j - 2 k