Physics, asked by roshanrs6433, 11 months ago

A magnetic field of 2×10⁻² T acts at right angles to a coil of area 100 cm⁻² with 50 turns. The average emf induced in the coil is 0.1 V, when it is removed from the field in time t. The value of t is(a) 0.1 sec(b) 0.01 sec(c) 1 sec(d) 20 sec

Answers

Answered by abhi178
26
magnetic field, B = 2 × 10^-2 T

cross sectional area , A = 100cm² = 10^-2 m²

number of turns , N = 50

induced emf , \xi = 0.1V

a/c to question, magnetic field acts at right angle to the coil.

so, just use the formula, induced emf = - change in magnetic flux/time

change in magnetic flux = final magnetic flux - initial magnetic flux = 0 - NBA

now, 0.1 = -(0 - NBA)/t

or, 0.1 = 50 × 2 × 10^-2 × 10^-2/t

or, t = 10^-2/0.1 = 0.1 sec

hence, the value of t will be 0.1 sec

so, option (a) is correct choice .
Answered by QHM
10

Explanation:

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