Question

a magnetic flux through a stationary loop with resistance R=5 ohm varies during the time interval of 10s as ϕ = 4t(10-t) where t denotes time and all the quantities are in SI units. The amount of heat generated in the loop in 10s is nearly​

Answer 1

Answer:

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Explanation:

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Answer 2

Given:

A magnetic flux through a stationary loop with resistance R=5 ohm varies during the time interval of 10s as ϕ = 4t(10-t) where t denotes time and all the quantities are in SI units.

To find:

The amount of heat generated in the loop in 10s is nearly ?

Calculation:

The EMF generated due to change in magnetic flux can be calculated as :

$\rm \therefore \: V = \dfrac{d \phi}{dt}$

$\rm \implies \: V = \dfrac{d \{4t(10 - t) \}}{dt}$

$\rm \implies \: V = \dfrac{d \{40t - {t}^{2} \}}{dt}$

$\rm \implies \: V = 40 - 2t$

$\rm \implies \: V = 40 - 2(10)$

$\rm \implies \: V = 20 \: volt$

Now , let heat generated be H :

$\rm \therefore \: H = \dfrac{ {V}^{2} }{r} \times t$

$\rm \implies\: H = \dfrac{ {(20)}^{2} }{5} \times 10$

$\rm \implies\: H = 400 \times 2$

$\rm \implies\: H = 800 \: joule$

So, heat generated in coil is 800 Joule.